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Question
Solve the following equation : `"ax"^2 + (4"a"^2 - 3"b")"x" - 12"ab" = 0`
Solution
`"ax"^2 + (4"a"^2 - 3"b")"x" - 12"ab" = 0`
`"x"^2 + 4"ax" - 3 "b"/"a" "x" - 12 "b" = 0`
`"x"("x" + 4"a") - 3 "b"/"a" ("x" + 4"a") = 0`
`("x + 4a")("x" - 3 "b"/"a") = 0`
x = -4a , x = `3 "b"/"a"`
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