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Question
Solve the following equation: `10"x" - 1/"x" = 3`
Solution
`10"x" - 1/"x" = 3`
10x2 - 1 = 3x
10x2 - 3x - 1 = 0
`"x"^2 - 3/10 "x" - 1/10 = 0`
`"x"^2 + 1/5 "x" - 1/2 "x" - 1/10 = 0`
`"x" ("x" + 1/5) - 1/2 ("x" + 1/5) = 0`
`("x" + 1/5)("x" - 1/2) = 0`
`("x" + 1/5) = 0` , `("x" - 1/2) = 0`
x = `-1/5` , `x = 1/2`
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