Advertisements
Advertisements
Question
Solve the following quadratic equation using formula method only
`2x^2 - 2 . sqrt 6x + 3 = 0`
Solution
`2x^2 - 2 . sqrt 6x + 3 = 0`
a = 2 ; b = `-2 sqrt 6` ; c =3
D = `"b"^2 - 4 "ac"`
`= (- 2 sqrt 6)^2 - 4(2)(3)`
= 24 - 24
= 0
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(-(- 2 sqrt 6) +- 0)/(2 xx 2)`
x = `sqrt 6/2`
APPEARS IN
RELATED QUESTIONS
Find that non-zero value of k, for which the quadratic equation kx2 + 1 − 2(k − 1)x + x2 = 0 has equal roots. Hence find the roots of the equation.
Find the values of k for which the roots are real and equal in each of the following equation:
9x2 - 24x + k = 0
Determine the nature of the roots of the following quadratic equation :
x2 -5x+ 7= 0
Find, using the quadratic formula, the roots of the following quadratic equations, if they exist
3x2 – 5x + 2 = 0
From the quadratic equation if the roots are 6 and 7.
Find if x = – 1 is a root of the equation 2x² – 3x + 1 = 0.
Determine whether the given values of x is the solution of the given quadratic equation below:
6x2 - x - 2 = 0; x = `(2)/(3), -1`.
In each of the following, determine whether the given numbers are roots of the given equations or not; x2 – x + 1 = 0; 1, – 1
Find whether the following equation have real roots. If real roots exist, find them.
5x2 – 2x – 10 = 0
The roots of the quadratic equation px2 – qx + r = 0 are real and equal if ______.
