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Question
Solve the following simultaneous equations
`1/(3x)-1/(4y)+1=0`;
`1/(5x)+1/(2y)=4/15`
Solution
`1/(3x)-1/(4y)+1=0` and `1/(5x)+1/(2y)=4/15`
`1/(3x)-1/(4y)=-1` and `1/(5x)+1/(2y)=4/15`
Let `1/x=a` and `1/y=b`
`a/3-b/4=-1` and `a/5+b/2=4/15`
`4a-3b=-12 and 2a+5b=40/15`
`4a-3b=-12 and 2a+5b=8/3`
`4a-3b=-12 and 6a+15b=8`
Solving thetwo equations, we get a=-2 and b=4/3
resubstituting `1/x=a and 1/y=b`
`=>x=-1/2 and y=3/4`
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