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Question
Solve the following:
`(3t + 5)/4 - 1 = (4t - 3)/5`
Solution
Given, `(3t + 5)/4 - 1 = (4t - 3)/5`
⇒ `(3t + 5 - 4)/4 = (4t - 3)/5`
⇒ 5(3t + 5 – 4) = 4(4t – 3) ...[By cross-multiplication]
⇒ 5(3t + 1) = 4(4t – 3)
⇒ 15t + 5 = 16t – 12
⇒ 15t – 16t = – 12 – 5 ...[Transposing 16t to LHS and 5 to RHS]
⇒ – t = – 17
⇒ `(-t)/(-1) = (-17)/(-1)` ...[Dividing both sides by –1]
∴ t = 17
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