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Question
Solve the following equation and check your result:
4z + 3 = 6 + 2z
Solution
4z + 3 = 6 + 2z
On transposing 2z to L.H.S and 3 to R.H.S, we obtain,
4z − 2z = 6 − 3
2z = 3
Dividing both sides by 2, we obtain
`z = 3/2`
L.H.S = 4z + 3 = 4 × `(3/2)` + 3
= 6 + 3
= 9
R.H.S = 6 + 2z
= 6 + 2 × `(3/2)`
= 6 + 3
= 9
L.H.S. = R.H.S.
Hence, the result obtained above is correct.
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