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Question
Solve the following equation by factorization
x2 – (p + q)x + pq = 0
Solution
x2 – (p + q)x + pq = 0
x2 - px - qx + pq = 0
x(x - p) -q)x - p) = 0
⇒ (x - p) (x - q) = 0
Either x - p = 0,
then x = p
or
x - q = 0,
then x = q
Hence x = p, q.
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