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Question
Solve the following equation by the trial-and-error method: 2y + 4 = 3y
Solution
2y + 4 = 3y
We try several values of y until we get the L.H.S. equal to the R.H.S.
| y | L.H.S. | R.H.S. | Is L.H.S. = R.H.S.? |
| 1 | 2 ×× 1 + 4 = 6 | 3 ×× 1 = 3 | No |
| 2 | 2 ×× 2 + 4 = 8 | 3 ×× 2 = 6 | No |
| 3 | 2 ×× 3 + 4 = 10 | 3 ×× 3 = 9 | No |
| 4 | 2 ×× 4 + 4 = 12 | 3 ×× 4 = 12 | Yes |
∴ y = 4
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|
m |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
______ |
|
m + 10 |
______ |
______ |
______ |
______ |
______ |
______ |
______ |
______ |
______ |
______ |
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