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Solve the following problem : Find the Quantity Index Number using Simple Aggregate Method. - Mathematics and Statistics

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Question

Solve the following problem :

Find the Quantity Index Number using Simple Aggregate Method.

Commodity Base year quantity Current year quantity
A 100 130
B 170 200
C 210 250
D 90 110
E 50 150
Sum

Solution

Commodity Base Year
Quantity q0
Current Year
Quantity q1
A 100 130
B 170 200
C 210 250
D 90 110
E 50 150
Total 620 840

From the table, `sum"q"_0 = 620, sum"q"_1 = 840`

Quantity Index Number (Q01) = `(sum"q"_1)/(sum"q"_0) xx 100`

= `(840)/(620) xx 100`

= 135.48

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Chapter 5: Index Numbers - Miscellaneous Exercise 5 [Page 92]

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Base year Quantity 140 120 100 200 225
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Base Year Price (in ₹) 10 8 12 24 18
Current Year Price (in ₹) 14 10 x 28 22

Find values x and y if the Price Index Number by Simple Aggregate Method by taking 2001 as base year is 120, given `sum"p"_1` = 300.

Commodity A B C D
Price (in ₹) in 2001 90 x 90 30
Price (in ₹) in 2004 95 60 y 35

Choose the correct pair:

Group A Group B
A. Price Index (a) `(sump_1q_1)/(sump_0q_0) xx 100`
B. Value Index (b) `(sumq_1)/(sumq_0) xx 100`
C. Quantity Index (c) `(sump_1q_1)/(sump_0q_1) xx 100`
D. Paasche's Index (d) `(sump_1)/(sump_0) xx 100`

Choose the correct pair :

Group A Group B
1) Price Index a) `(sum p_1q_1)/(sum p_0q_0) xx 100`
2) Value Index b) `(sum q_1)/(sum q_0) xx 100`
3) Quantity Index c) `(sum p_1q_1)/(sum p_0 q_1) xx 100`
4) Paasche's Index d) `(sum p_1)/(sum p_0) xx 100`

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Group A Group B
1) Price Index a) `(sump_1q_1)/(sump_0 q_0) × 100`
2) Value Index b) `(sumq_1)/(sumq_0) × 100`
3) Quantity Index c) `(sump_1q_1)/(sump_0 q_1) × 100`
4) Paasche's Index d) `(sump_1)/(sump_0) × 100`

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2) Value Index b) `(sumq1)/(sumq0)xx100`
3) Quantity Index c) `(sump1q1)/(sump0q1)xx100`
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1) Price Index a) `(sump_1q_1)/(sump_0q_0) xx 100`
2) Value Index b) `(sumq_1)/(sumq_0) xx 100`
3) Quantity Index c) `(sump_1q_1)/(sump_0q_1) xx 100`
4) Paasche's Index d) `(sump_1)/(sump_0) xx 100`

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1) Price Index a) `(sum"p"_1"q"_1)/(sum"p"_0"q"_0)xx100`
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4) Paasche's Index d) `(sum"p"_1)/(sum"p"_0")xx100`

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