Solve the following quadratic equation: x2 + 3ix + 10 = 0 - Mathematics and Statistics

Solve the following quadratic equation:

x² + 3ix + 10 = 0

Sum

Given equation is x² + 3ix + 10 = 0
Comparing with ax² + bx + c = 0, we get
a = 1, b = 3i, c = 10
Discriminant = b² – 4ac

= (3i)² – 4 x 1 x 10

= 9i² – 40

= – 9 – 40 ...[∵ i² = – 1]

= – 49 < 0
So, the given equation has complex roots.
These roots are given by

x = `(-"b" ± sqrt("b"^2 - 4"ac"))/(2"a")`

= `(-3"i" ± sqrt(-49))/(2(1)`

∴ x = `(-3"i" + 7"i")/2`

∴ x = `(-3"i" + 7"i")/2 or x = (-3"i" - 7"i")/2`

∴ x = 2i or x = – 5i
∴ the roots of the given equation are 2i and – 5i.

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Solution of a Quadratic Equation in Complex Number System

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Chapter 3: Complex Numbers - EXERCISE 3.2 [Page 40]

Chapter 3 Complex Numbers
EXERCISE 3.2 | Q 3) i) | Page 40

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