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Question
Solve the following riddles, you may yourself construct such riddles.
| Who am I? |
 |
| I am a special number Take away from me a six! A whole cricket team You will still be able to fix! |
Solution
In a cricket team, there are 11 players.
Hence, the number is such that when 6 is subtracted from it, the result is 11.
Therefore, the number is 11 + 6 = 17.
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RELATED QUESTIONS
Complete the last column of the table.
| Equation | Value | Say, whether the Equation is Satisfied. (Yes/No) |
| `m/3 = 2` | m = -6 |
Write equation for the following statement.
The sum of numbers x and 4 is 9.
Write equation for the following statement:
One-fourth of a number x minus 4 gives 4.
By how much is 2x − 3y + 4z greater than 2x + 5y − 6z + 2?
Verify by substitution that the root of 3x − 5 = 7 is x = 4.
Verify by substitution that the root of 3 + 2x = 9 is x = 3.
Write 'T' for true and 'F' for false for the statement given below:
`x=2/3` is solution of 2x + 5 = 8.
A shopkeeper sells mangoes in two types of boxes, one small and one large. A large box contains as many as 8 small boxes plus 4 loose mangoes. Set up an equation which gives the number of mangoes in each small box. The number of mangoes in a large box is given to be 100.
State which of the following are equations (with a variable). Give reason for your answer. Identify the variable from the equations with a variable.
20 − (10 − 5) = 3 × 5
Complete the entries in the third column of the table.
|
S.No. |
Equation |
Value of variable |
Equation satisfied Yes/No |
|
(a) |
10y = 80 |
y = 10 |
______ |
|
(b) |
10y = 80 |
y = 8 |
______ |
|
(c) |
10y = 80 |
y = 5 |
______ |
|
(d) |
4l = 20 |
l = 20 |
______ |
|
(e) |
4l = 20 |
l = 80 |
______ |
|
(f) |
4l = 20 |
l = 5 |
______ |
|
(g) |
b + 5 = 9 |
b = 5 |
______ |
|
(h) |
b + 5 = 9 |
b = 9 |
______ |
|
(i) |
b + 5 = 9 |
b = 4 |
______ |
|
(j) |
h − 8 = 5 |
h = 13 |
______ |
|
(k) |
h − 8 = 5 |
h = 8 |
______ |
|
(l) |
h − 8 = 5 |
h = 0 |
______ |
|
(m) |
p + 3 = 1 |
p = 3 |
______ |
|
(n) |
p + 3 = 1 |
p = 1 |
______ |
|
(o) |
p + 3 = 1 |
p = 0 |
______ |
|
(p) |
p + 3 = 1 |
p = − 1 |
______ |
|
(q) |
p + 3 = 1 |
p = − 2 |
______ |
