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Solve: (x-10)(1200x+2)=1260 and x < 0 - Mathematics

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Question

Solve:

`( x - 10)(1200/x + 2) = 1260` and x < 0

Sum

Solution

Given quadratic equation is `(x - 10)(1200/x + 2) = 1260`

`=> (x - 10)(1200/x + 2) = 1260`

`=>` (x – 10)(1200 + 2x) = 1260x

`=>` 1200x + 2x2 – 12000 – 20x – 1260x

`=>` 2x2 – 12000 – 80x = 0

`=>` x2 – 40x – 6000 = 0

`=>` x2 – 100x + 60x – 6000 = 0

`=>` (x = 100)(x + 60) = 0

`=>` x = 100 or x = – 60

But as x < 0, so x can't be positive.

Hence, x = – 60

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Chapter 5: Quadratic Equations - Exercise 5 (F) [Page 67]

APPEARS IN

Selina Mathematics [English] Class 10 ICSE
Chapter 5 Quadratic Equations
Exercise 5 (F) | Q 13.2 | Page 67
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