Question

सोपे रूप द्या.

`(3x^2 - x - 2)/(x^2 - 7x + 12) ÷ (3x^2 - 7x - 6)/(x^2 - 4)`

Answer 1

आपणांस माहीत आहे की,

a³ − b³ = (a − b)(a² + ab + b²)

= `(3x^2 - x - 2)/(x^2 - 7x + 12) xx (x^2 - 4)/(3x^2 - 7x - 6)`

= `(3x^2 - 3x + 2x - 2)/(x^2 - 4x - 3x + 12) xx (x^2 - 2^2)/(3x^2 - 9x + 2x - 6)`

= `(3x(x - 1) + 2(x - 1))/(x(x - 4) - 3(x - 4)) xx ((x + 2)(x - 2))/(3x(x - 3) + 2(x - 3))`

= `((x - 1)(3x + 2))/((x - 4)(x - 3)) xx ((x + 2)(x - 2))/((x - 3)(3x + 2))`

= `((x - 1)(x + 2)(x - 2))/((x - 4)(x - 3)^2)`