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सोपे रूप द्या. x2-5x-24(x+3)(x+8)×x2-64(x-8)2 - Mathematics [गणित]

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Question

सोपे रूप द्या.

`(x^2 - 5x - 24)/((x + 3)(x + 8)) xx (x^2 - 64)/((x - 8)^2)`

Simplify

Solution

आपणांस माहीत आहे की,

a2 − b= (a + b) (a − b)

a3 − b3 = (a − b)(a2 + ab + b2)

`(x^2 - 5x - 24)/((x + 3)(x + 8)) xx (x^2 - 64)/((x - 8)^2)`

= `(x^2 - 8x + 3x - 24)/((x + 3)(x + 8)) xx ((x)^2 - (8)^2)/(x - 8)^2`

= `(x(x - 8) + 3(x - 8))/((x + 3)(x + 8)) xx ((x + 8)(x - 8))/((x - 8)(x - 8))`

= `((x + 3)(x - 8))/((x + 3)(x + 8)) xx ((x + 8)(x - 8))/((x - 8)(x - 8))`

= 1

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Chapter 3.1: बैजिक राशींचे अवयव - सरावसंच 6.4 [Page 56]

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Balbharati Integrated 8 Standard Part 2 [Marathi Medium] Maharashtra State Board
Chapter 3.1 बैजिक राशींचे अवयव
सरावसंच 6.4 | Q 1. (4) | Page 56
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