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सोपे रूप द्या. 8x3-27y34x2-9y2 - Mathematics [गणित]

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Question

सोपे रूप द्या.

`(8x^3 - 27y^3)/(4x^2 - 9y^2)`

Simplify

Solution

आपणांस माहीत आहे की,

a2 − b= (a + b) (a − b)

a3 − b3 = (a − b)(a2 + ab + b2)

`(8x^3 - 27y^3)/(4x^2 - 9y^2)`

= `((2x)^3 - (3y)^3)/((2x)^2 - (3y)^2)`

= `((2x - 3y)[(2x)^2 + (2x) xx (3y) + (3y)^2])/((2x + 3y)(2x - 3y))`

= `((2x - 3y) (4x^2 + 6xy + 9y^2))/((2x + 3y)(2x - 3y))`

= `(4x^2 + 6xy + 9y^2)/(2x + 3y)`

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Chapter 3.1: बैजिक राशींचे अवयव - सरावसंच 6.4 [Page 56]

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Balbharati Integrated 8 Standard Part 2 [Marathi Medium] Maharashtra State Board
Chapter 3.1 बैजिक राशींचे अवयव
सरावसंच 6.4 | Q 1. (3) | Page 56
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