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Question
`sqrt3x^2+10x+7sqrt3=0`
Solution
`sqrt3x^2+10x+7sqrt3=0`
⇒`3x^2+10sqrt3x+21=0` (Multiplying both sides by `sqrt3` )
⇒`3x^2+10sqrt3x=-21`
⇒`(sqrt3x)^2+2xxsqrt3x xx5+5^2=-21+5^2` (Adding `5^2` on both sides)
⇒`(sqrt3x+5)^2=21+25=4=2^2`
⇒`sqrt3x+5=+-2` (Taking square root on both sides)
⇒`sqrt3x+5=2 or sqrt3x+5=-2`
⇒`sqrt3x=-3 or sqrt3x=-7`
⇒`x=-3/sqrt3=sqrt3 or x=-7/sqrt3=-7sqrt3/3`
Hence, `-sqrt3` and `-(7sqrt3)/3` are the roots of the given equation.
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