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Question
Find the value of discriminant.
`sqrt2x^2 + 4x + 2sqrt2 = 0`
Solution
`sqrt2x^2 + 4x + 2sqrt2 = 0`
Comparing the given equation with ax2 + bx + c = 0, we get,
`a = sqrt2, b = 4, c = 2sqrt2`
So, the discriminant (D),
`∴ b^2 − 4ac = (4)^2 − 4 × (sqrt2) × (2sqrt2)`
`∴ b^2 − 4ac = 16 − 16`
`∴ b^2 − 4ac = 0`.
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