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Question
Determine the nature of roots of the following quadratic equation.
x2 – 4x + 4 = 0
Solution
x2 – 4x + 4 = 0 Comparing the given equation with the quadratic equation \[a x^2 + bx + c = 0\] \[a = 1, b = - 4, c = 4\] Discriminant, \[\bigtriangleup = b^2 - 4ac = \left( - 4 \right)^2 - 4 \times 1 \times 4 = 16 - 16 = 0\]
Since the discriminant = 0 so, the roots of the given quadratic equation are real and equal.
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