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Question
Solve the following quadratic equation for x:
`4sqrt3x^2+5x-2sqrt3=0`
Solution 1
`4sqrt3x^2+5x-2sqrt3=0`
`rArr4sqrt3x^2+8x-3x-2sqrt3=0`
`rArr4x(sqrt3x+2)-sqrt3(sqrt3x+2)=0`
`rArr(4x-sqrt3)(sqrt3x+2)=0`
`therefore x=sqrt3/4` or `x=-2/sqrt3`
Solution 2
`4sqrt3x^2+5x-2sqrt3=0`
`rArr4sqrt3x^2+8x-3x-2sqrt3=0`
`rArr4x(sqrt3x+2)-sqrt3(sqrt3x+2)=0`
`rArr(4x-sqrt3)(sqrt3x+2)=0`
`therefore x=sqrt3/4` or `x=-2/sqrt3`
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