English

सरल कीजिए - 49×z-37-3×10×z-5(z≠0) - Mathematics (गणित)

Advertisements
Advertisements

Question

सरल कीजिए -

`(49 xx z^-3)/(7^-3 xx 10 xx z^-5) (z ≠ 0)`

Simplify

Solution

`(49 xx z^-3)/(7^-3 xx 10 xx z^-5) = ((7)^2 xx z^-3)/(7^-3 xx 10 xx z^-5)`

= `((7)^(2 + 3) xx z^(-3 + 5))/10`  ...[∵ am ÷ an = (a)m – n]

= `((7)^5 z^2)/10`

= `7^5/10 z^2`

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: घातांक और घात - प्रश्नावली [Page 253]

APPEARS IN

NCERT Exemplar Mathematics [Hindi] Class 8
Chapter 8 घातांक और घात
प्रश्नावली | Q 98. (iii) | Page 253
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×