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Question
Subtract:
2ab + cd − ac − 2bd from ab − 2cd + 2ac + bd.
Solution
(ab − 2cd + 2ac + bd) − (2ab + cd − ac − 2bd)
= ab − 2cd + 2ac + bd − 2ab − cd + ac + 2bd
= ab − 2ab − 2cd − cd + 2ac + ac + bd + 2bd
= − ab − 3cd + 3ac + 3bd
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