Advertisements
Advertisements
Question
Subtract the second expression from the first.
(5x + 4y + 7z); (x + 2y + 3z)
Sum
Solution
(5x + 4y + 7z) − (x + 2y + 3z)
= 5x + 4y + 7z − x − 2y − 3z
= (5x − x) + (4y − 2y) + ( 7z − 3z)
= 4x + 2y + 4z
shaalaa.com
Is there an error in this question or solution?
RELATED QUESTIONS
Subtract the second expression from the first.
(4x + 16z); (19y − 14z + 16x)
Subtract 5x2 – 4y2 + 6y – 3 from 7x2 – 4xy + 8y2 + 5x – 3y.
Subtract: 7xyz from 17xyz
Subtract: 2y + z from 6z – 5y
Subtract – 3ab – 8 from 3ab + 8. Also, subtract 3ab + 8 from – 3ab – 8
What should be subtracted from 2m + 8n + 10 to get – 3m + 7n + 16?
Subtract the following expressions:
x4 + 3x3y3 + 5y4 from 2x4 – x3y3 + 7y4
Subtract the following expressions:
–2a2 – 2b2 from –a2 – b2 + 2ab
If P = –(x – 2), Q = –2(y + 1) and R = –x + 2y, find a, when P + Q + R = ax.
Subtract the sum of 12ab – 10b2 – 18a2 and 9ab + 12b2 + 14a2 from the sum of ab + 2b2 and 3b2 – a2.