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Taking x = -49, y = 512 and z = 718, find the sum of reciprocals of x and y - Mathematics

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Question

Taking x = `(-4)/9`, y = `5/12` and z = `7/18`, find the sum of reciprocals of x and y

Sum

Solution

Given, x = `(-4)/9`, y = `5/12` and z = `7/18`

Reciprocal of x and y is `1/x` and `1/y`

∴ Sum of reciprocals = `1/x + 1/y = 1/((-4)/9) + 1/(5/12)`

= `(-9)/4 + 12/5`  ......[∵ LCM of 4 and 5 = 20]

= `(-45 + 48)/20`  

= `3/20`

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Chapter 8: Rationals Numbers - Exercise [Page 251]

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NCERT Exemplar Mathematics [English] Class 7
Chapter 8 Rationals Numbers
Exercise | Q 94. (f) | Page 251

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