Advertisements
Advertisements
Question
Test the continuity of the following function at the points indicated against them:
f(x) = 4x + 1, for x ≤ 3
= `(59 - 9x)/3`, for x > 3 at x = `8/3`.
Solution
`lim_(x→(8/3)^-) "f"(x) = lim_(x→(8/3)^-) (4x + 1)`
= `4(8/3) + 1`
= `32/3 + 1`
= `35/3`
`lim_(x→(8/3)^+) "f"(x) = lim_(x→(8/3)^+) (59 - 9x)/3`
= `(59 - 9(8/3))/3`
= `(59 - 24)/3`
= `35/3`
f(x) = 4x + 1, x ≤ `(8/3)`
∴ `"f"(8/3) = 4(8/3) + 1`
= `32/3 + 1`
= `35/3`
`lim_(x→(8/3)^-) "f"(x) = lim_(x→(8/3)^+) "f"(x) = "f"(8/3)`
∴ f(x) is continuous at x = `8/3`
APPEARS IN
RELATED QUESTIONS
Test the continuity of the following function at the points indicated against them:
`f(x) = (sqrt(x - 1) - (x - 1)^(1/3))/(x - 2)` for x ≠ 2
= `1/5` for x = 2, at x = 2
Test the continuity of the following function at the points indicated against them:
`"f"(x) = (x^3 - 8)/(sqrt(x + 2) - sqrt(3x - 2))` for x ≠ 2
= – 24 for x = 2, at x = 2
Test the continuity of the following function at the points indicated against them:
f(x) = `(x^3 - 27)/(x^2 - 9)` for 0 ≤ x <3
= `9/2` for 3 ≤ x ≤ 6, at x = 3
Discuss the continuity of the following function at the point(s) or in the interval indicated against them:
f(x) = 2x2 − 2x + 5 for 0 ≤ x < 2
= `(1 - 3x - x^2)/(1 - x)` for 2 ≤ x < 4
= `(7 - x^2)/(x - 5)` for 4 ≤ x ≤ 7 on its domain.
Discuss the continuity of the following function at the point(s) or in the interval indicated against them:
`f(x) = (5^x - e^x)/(2x)` for x ≠ 0
= `1/2`(log5−1) for x = 0 at x = 0
`f(x) = (log x - log 3)/(x - 3)` for x ≠ 3
= 3 for x = 3, at x = 3.
Find a and b if the following function is continuous at the point indicated against them.
`f(x) = (x^2 - 9)/(x - 3) + "a"` , for x > 3
= 5 , x = 3
= 2x2 + 3x + b , for x < 3
is continuous at x = 3