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Question
The 17th term of an AP exceeds its 10th term by 7. Find the common difference.
Solution
We know that,
For an A.P., an = a + (n − 1) d
a17 = a + (17 − 1) d
a17 = a + 16d
Similarly, a10 = a + 9d
It is given that
a17 − a10 = 7
(a + 16d) − (a + 9d) = 7
7d = 7
d = `7/7`
d = 1
Therefore, the common difference is 1.
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