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Which term of the A.P. 3, 15, 27, 39, … will be 132 more than its 54th term? - Mathematics

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Question

Which term of the A.P. 3, 15, 27, 39, … will be 132 more than its 54th term?

Sum

Solution

a = 3, d = 15 - 3 = 12

Using Tn = a + (n - 1)d, we get

T54 = a + 53d

= 3 + 53 × 12

= 3 + 636

= 639

Let Tn be 132 more than its 54th term.

∴ Tn = T54 + 132

Tn = 639 + 132

Tn = 771

a + (n - l)d = 771

3 + (n - 1) × 12 = 771

(n - 1) × 12 = 771 - 3 

(n - 1) × 12 = 768

(n - 1) = `768/12`

(n - 1) = 64

n = 64 + 1

n = 65

Thus, 132 more than 54th term is the 65th term. 

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Chapter 5: Arithmetic Progressions - Exercise 5.2 [Page 106]

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NCERT Mathematics [English] Class 10
Chapter 5 Arithmetic Progressions
Exercise 5.2 | Q 11 | Page 106

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