Advertisements
Advertisements
Question
Write the first five terms of the following sequences whose nth term are:
`a_n = (n - 2)/3`
Solution
`a_n = (n - 2)/3`
Given sequence `a_n = (n - 2)`
To write first five terms of given sequence `a_n = (n - 2)/3`
put n = 1, 2, 3, 4, 5 then we get
`a_ 1 = (1 - 2)/3 = (-1)/3; a_2 = (2 - 2)/3 = 0`
`a_3 = (3-2)/3 = 1/3; a_4 = (4 -2)/3 = 2/3`
`a_5 = (5 - 2)/3 = 1`
∴ The required first five terms of given sequence `a_n = (n -2)/3` are `(-1)/3,0,1/3,2/3,1`
APPEARS IN
RELATED QUESTIONS
Choose the correct choice in the following and justify:
30th term of the AP: 10, 7, 4, ..., is ______.
Which term of the A.P. 3, 15, 27, 39, … will be 132 more than its 54th term?
Which term of the A.P. 3, 15, 27, 39, ... will be 120 more than its 21st term?
Find:
v) the 15the term of the AP - 40,- 15,10,35,.........
How many terms are there in the AP 41, 38, 35, ….,8?
Find the 15th term of an AP -2, -5, -8, ….
If 7 times the 7th term of an AP is equal to 11 times its 11th term, then its 18th term will be ______.
Two APs have the same common difference. The first term of one of these is –1 and that of the other is – 8. Then the difference between their 4th terms is ______.
Fill in the blank in the following table, given that a is the first term, d the common difference, and an nth term of the AP:
a | d | n | an |
-18 | ______ | 10 | 0 |
Determine the 36th term of the A.P. whose first two terms are –3 and 4 respectively.