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Question
Determine the 36th term of the A.P. whose first two terms are –3 and 4 respectively.
Solution
Given, first two terms of AP are –3 and 4.
∴ a1 = –3 and a2 = 4
∴ Common difference, d = 4 – (–3) = 4 + 3 = 7
We know that, nth term of A.P. is Tn = a + (n – 1)d
∴ T36 = a + (36 – 1)d
= –3 + 35(7)
= –3 + 245
= 242
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