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Question
Write the first five terms of the following sequences whose nth terms are:
`a_n = (3n - 2)/5`
Solution
`a_n = (3n - 2)/5`
Here, the nth term is given by the above expression. So, to find the first term we use, n =1 we get
`a_1 = (3(1) - 2)/5`
`= 1/5`
Similarly, we find the other four terms,
Second term (n = 2)
``a_2 = (3(2) - 2)/5`
`= (6 - 2)/5`
`= 4/5`
Third term (n = 3)
`a_3 = (3(3) - 2)/5`
`= (9 - 5)/5`
`= 7/5`
Fourth term (n = 4)
`a_4 = (3(4) - 2)/5`
`= (12 - 2)/5`
`= 10/5`
= 2
Fifth term (n = 5)
`a_5 = (3(5) - 2)/5`
`= (15 - 2)/5`
`= 13/5`
Therefore, the first five terms for the given sequence are `a_1 = 1/5, a_2 = 4/5,a_3 = 7/5, a_4 = 2, a_5 = 13/5`
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