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What is the common difference of an AP in which a18 – a14 = 32? - Mathematics

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Question

What is the common difference of an AP in which a18 – a14 = 32?

Options

  • 8

  • – 8

  • – 4

  • 4

MCQ

Solution

8

Explanation:

Given, a18 – a14 = 32

⇒ a + (18 – 1)d – [a + (14 – 1)d] = 32   ...[∵ an = a + (n – 1)d]

⇒ a + 17d – a – 13d = 32

⇒ 4d = 32

∴ d = 8

Which is the required common difference of an AP.

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Chapter 5: Arithematic Progressions - Exercise 5.1 [Page 46]

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NCERT Exemplar Mathematics [English] Class 10
Chapter 5 Arithematic Progressions
Exercise 5.1 | Q 10 | Page 46
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