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Question
Write the first five terms of the following sequence whose nth term is:
an = 2n2 − 3n + 1
Solution
an = 2n2 – 3n + 1
Put n = 1
A1 = 2(1)2 – 3(1) + 1 = 2 – 3 + 1 = 0
Put n = 2
A2 = 2(2)2 – 3(2) + 1 = 8 – 6 + 1 = 3
Put n = 3
A3 = 2(3)2 – 3(3) + 1 = 18 – 9 + 1 = 10
Put n = 4
A4 = 2(4)2 – 3(4) + 1 = 32 – 12 + 1 = 21
Put n = 5
A5 = 2(5)2 – 3(5) + 1 = 50 – 15 + 1 = 36
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