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Determine the AP whose fifth term is 19 and the difference of the eighth term from the thirteenth term is 20. - Mathematics

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Question

Determine the AP whose fifth term is 19 and the difference of the eighth term from the thirteenth term is 20.

Sum

Solution

We know that,

The first term of an AP = a

And the common difference = d

According to the question,

5th term, a5 = 19

Using the nth term formula,

an = a + (n – 1)d

We get,

a + 4d = 19

a = 19 – 4d   ...(1)

Also,

13th term – 8th term = 20

a + 12d – (a + 7d) = 20

5d = 20

d = 4

Substituting d = 4 in equation 1,

We get,

a = 19 – 4(4)

a = 3

Then, the AP becomes,

3, 3 + 4, 3 + 2(4),...

3, 7, 11,...

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Chapter 5: Arithematic Progressions - Exercise 5.3 [Page 52]

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NCERT Exemplar Mathematics [English] Class 10
Chapter 5 Arithematic Progressions
Exercise 5.3 | Q 5. | Page 52
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