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Question
Determine the AP whose fifth term is 19 and the difference of the eighth term from the thirteenth term is 20.
Solution
We know that,
The first term of an AP = a
And the common difference = d
According to the question,
5th term, a5 = 19
Using the nth term formula,
an = a + (n – 1)d
We get,
a + 4d = 19
a = 19 – 4d ...(1)
Also,
13th term – 8th term = 20
a + 12d – (a + 7d) = 20
5d = 20
d = 4
Substituting d = 4 in equation 1,
We get,
a = 19 – 4(4)
a = 3
Then, the AP becomes,
3, 3 + 4, 3 + 2(4),...
3, 7, 11,...
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