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प्रश्न
Which term of the A.P. 3, 15, 27, 39, … will be 132 more than its 54th term?
उत्तर
a = 3, d = 15 - 3 = 12
Using Tn = a + (n - 1)d, we get
T54 = a + 53d
= 3 + 53 × 12
= 3 + 636
= 639
Let Tn be 132 more than its 54th term.
∴ Tn = T54 + 132
Tn = 639 + 132
Tn = 771
a + (n - l)d = 771
3 + (n - 1) × 12 = 771
(n - 1) × 12 = 771 - 3
(n - 1) × 12 = 768
(n - 1) = `768/12`
(n - 1) = 64
n = 64 + 1
n = 65
Thus, 132 more than 54th term is the 65th term.
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