Advertisements
Advertisements
Question
The abscissa of a point A is equal to its ordinate, and its distance from the point B(1, 3) is 10 units, What are the coordinates of A?
Solution
Let the point A be (a, a) B is (1, 3)
Distance AB = 10 ...(Given)
By distance formula `sqrt(("a" - 1)^2 + ("a" - 3)^2` = 10
Simplifying 2a2 – 8a + 10 = 100
a2 – 4a – 45 = 0
(a – 9)(a + 5) = 0
⇒ a = – 5, A = (– 5, – 5)
a = 9, A = (9, 9)
APPEARS IN
RELATED QUESTIONS
Find the distance with the help of the number line given below.
d (Q, B)
If the co-ordinate of A is x and that of B is y, find d(A, B).
x = 6, y = - 2
If the co-ordinate of A is x and that of B is y, find d(A, B).
x = 4, y = - 8
Sketch proper figure and write the answer of the following question.
If X-Y-Z and l(XZ) = `3sqrt7`, l(XY) = `sqrt7`, then l(YZ) = ?
Find d(A, B), if co-ordinates of A and B are -2 and 5 respectively.
Co-ordinates of the pair of points are given below. Hence find the distance between the pair.
- 4, 5
Show that the following points taken in order to form the vertices of a parallelogram
A(−3, 1), B(−6, −7), C(3, −9) and D(6, −1)
Show that the following points taken in order to form the vertices of a parallelogram
A(−7, −3), B(5, 10), C(15, 8) and D(3, −5)
Find the distance with the help of the number line given below.
d(J, A)
Find the distance with the help of the number line given below.
d(P, C)
