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Question
The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?
Solution
Amplitude of magnetic field of an electromagnetic wave in a vacuum,
B0 = 510 nT = 510 × 10−9 T
Speed of light in a vacuum, c = 3 × 108 m/s
Amplitude of electric field of the electromagnetic wave is given by the relation,
E = cB0
= 3 × 108 × 510 × 10−9
= 153 N/C
Therefore, the electric field part of the wave is 153 N/C.
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