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Maharashtra State BoardSSC (English Medium) 7th Standard

The Area of a Rectangular Garden of Length 40 M, is 1000 Sqm. Find the Breadth of the Garden and Its Perimeter. the Garden is to Be Enclosed by 3 Rounds of Fencing, Leaving an Entrance of 4 M. - Mathematics

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Question

The area of a rectangular garden of length 40 m, is 1000 sqm. Find the breadth of the garden and its perimeter. The garden is to be enclosed by 3 rounds of fencing, leaving an entrance of 4 m. Find the cost of fencing the garden at a rate of 250 rupees per metre.

Sum

Solution

Length of the garden = 40 m

Area = 1000 sq m

⇒ lb = 1000

⇒ 40b = 1000

⇒ b = 25 m

Perimeter = 2 (l + b) = 2 (40 + 25) = 130 m

For 1 round of fencing leaving the entrance of 4 m, the length of wire required = 130 m - 4 m = 126 m

For 3 such rounds of fencing, 3 × 126 m = 378 m of wire required.

Rate of fencing 1 m = Rs 250

Rate of fencing 378 m = 378 × 250 = Rs. 94500

Thus, Rs 94500 is required for fencing the garden. 

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Chapter 17: Miscellaneous Problems : Set 2 - Exercise [Page 100]

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Balbharati Mathematics [English] 7 Standard Maharashtra State Board
Chapter 17 Miscellaneous Problems : Set 2
Exercise | Q 8 | Page 100
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