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Question
A school playground is divided by a 2 m wide path which is parallel to the width of the playground, and a 3 m wide path which is parallel to the length of the ground in the given figure. If the length and width of the playground are 120 m and 80 m respectively, find the area of the remaining playground.
Solution
Given, dimensions of playground = 120 m × 80 m
∵ Area of rectangle ABCD = 120 × 80 = 9600 m2
Area of rectangle ABFE = AB × BF
= 120 × 3 = 360 m2 ......[∵ Area of rectangle = Length × Breadth]
Area of rectangle GHIJ = JI × IH = 2 × 77 = 154 m2
∴ Area of remaining ground rectangle GHIJ = Area of rectangle ABCD – Area of rectangle ABFE – Area of GHIJ
= 9600 – 360 – 154
= 9086 m2
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