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Question
The base of an isosceles triangle is `4/3` cm. The perimeter of the triangle is `4 2/15` cm. What is the length of either of the remaining equal sides?
Solution
Let the length of equal sides be x cm
Perimeter = x cm + x cm + Base = `4 2/15` cm.
`2x + 4/3 = 62/15`
On transposing `4/3` to R.H.S, we obtain
`2x = 62/15 - 4/3`
`2x = (62 - 4 xx 5)/15 = (62-20)/15`
`2x = 42/15`
On dividing both sides by 2, we obtain
`(2x)/2 = 42/15 xx 1/2`
`x = 7/5 = 1 2/5`
Therefore, the length of equal sides is `1 2/5` cm
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