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Question
Solve the following equation and check your result:
`(2x)/3 + 1 = (7x)/15 + 3`
Solution
`(2x)/3 + 1 = (7x)/15 + 3`
Transposing `(7x)/15` to L.H.S and 1 to R.H.S, we obtain
`(2x)/3 - (7x)/15 = 3 - 1`
`(5 xx 2x - 7x)/15 = 2`
`(3x)/15 = 2`
`x/5 = 2`
Multiplying both sides by 5, we obtain
x = 10
L.H.S = `(2x)/3 + 1`
`= (2xx10)/3 + 1`
`= (2 xx 10 + 1 xx 3)/3 `
`= 23/3`
R.H.S = `(7x)/15 + 3`
`= (7 xx 10)/15 + 3`
`= (7 xx 2)/3 + 3`
`= 14/3 + 3`
`= (14 + 3 xx 3)/3`
`= 23/3`
L.H.S. = R.H.S.
Hence, the result obtained above is correct.
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