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Solve the following: 4(3p + 2) – 5(6p – 1) = 2(p – 8) – 6(7p – 4) - Mathematics

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Question

Solve the following:

4(3p + 2) – 5(6p – 1) = 2(p – 8) – 6(7p – 4)

Sum

Solution

Given, 4(3p + 2) – 5(6p – 1) = 2(p – 8) – 6(7p – 4)

⇒ 12p + 8 – 30p + 5 = 2p – 16 – 42p + 24

⇒ –18p + 13 = – 40p + 8

⇒ –18p + 40p = 8 – 13  ...[Transposing – 40p to LHS and 13 to RHS]

⇒ 22p = – 5

⇒ `(22p)/22 = (-5)/22`  ...[Dividing both sides by 22]

∴ `p = (-5)/22`

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Chapter 4: Linear Equation In One Variable - Exercise [Page 117]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 4 Linear Equation In One Variable
Exercise | Q 76. | Page 117

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