Question

The centre of a circle is at (2, 0). If one end of a diameter is at (6, 0), then the other end is at ______.

Options

• (0, 0)

• (4, 0)

• (−2, 0)

• (−6, 0)

Answer 1

The centre of a circle is at (2, 0). If one end of a diameter is at (6, 0), then the other end is at (−2, 0).

Explanation:

Here, centre C is mid-point of AB.

∴ 2 = ${\displaystyle \frac{6+x}{2}}$ and

0 = ${\displaystyle \frac{0+y}{2}}$

⇒ x = −2 and y = 0

Thus, B(x, y) = (−2, 0)