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Question
The conductivity of 0.20 M solution of \[\ce{KCl}\] at 298 K is 0.0248 S cm−1. Calculate its molar conductivity.
Solution
`∧_"m" = (κ xx 1000)/("Molarity")`
= `(0.0248 "S cm"^-1 xx 1000 "cm"^3 "L"^-1)/(0.20 "mol L"^-1)`
= 124 S cm2 mol−1
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