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The cost of a machine depreciated by Rs. 4,000 during the first year and by Rs. 3,600 during the second year. Calculate: 1. The rate of depreciation. 2. The original cost of the machine. - Mathematics

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Question

The cost of a machine depreciated by Rs. 4,000 during the first year and by Rs. 3,600 during the second year. Calculate :

  1. The rate of depreciation.
  2. The original cost of the machine.
  3. Its cost at the end of the third year.
Sum

Solution

(i) Difference between depreciation in value between the first and second years Rs. 4,000 - Rs. 3,600 = Rs. 400.

⇒ Depreciation of one year on Rs. 4,000 = Rs. 400

⇒ Rate of depreciation = `400/4000 xx 100%` = 10%

(ii) Let Rs. 100 be the original cost of the machine.

Depreciation during the 1st year = 10% of Rs. 100 = Rs. 10

When the values depreciates by Rs. 10 during the 1st year, Original cost = Rs. 100

⇒ When the depreciation during 1st year = Rs. 4,000

Original Cost = `100/10 xx 4000` = Rs. 40,000

The original cost of the machine is Rs. 40,000.

(iii) Total depreciation during all the three years

= Depreciation in value during (1st year + 2nd year + 3rd year)

= Rs. 4,000 + Rs. 3,600 + 10% of (Rs. 40,000 - Rs. 7,600)

= Rs. 4,000 + Rs. 3,600 + Rs. 3,240

= Rs. 10,840

The cost of the machine at the end of the third year

= Rs. 40,000 - Rs. 10,840 = Rs. 29,160

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Chapter 2: Compound Interest (Without using formula) - Exercise 2 (C) [Page 38]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 2 Compound Interest (Without using formula)
Exercise 2 (C) | Q 9 | Page 38

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