Question

The diameter of zinc atom is 2.6 Å. Calculate

1. radius of zinc atom in pm and
2. number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side length-wise.

Answer 1

a) Radius of zinc atom = `"Diameter"/2`

`= (2.6 Å)/2`

`= 1.3 xx 10^(-10) " m"`

`=130xx10^(-12) " m" = 130 " pm"`

b) Length of the arrangement = 1.6 cm

= 1.6 × 10^-2 m

Diameter of zinc atom = 2.6 × 10^-10 m

∴ Number of zinc atoms present in the arrangement

`= (1.6xx10^(-2) " m")/(2.6 xx 10^(-10) " m")`

`= 0.6153 xx 10^8 " m"`

`= 6.153xx10^7`