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The Dimensions of a Rectangular Box Are in the Ratio 4: 2 : 3. the Difference Between the Cost of Covering It with Paper at Rs. 12 per M2 and with Paper at the Rate of 13.50 per M2 is Rs. 1,248 - Mathematics

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Question

The dimensions of a rectangular box are in the ratio 4: 2 : 3. The difference between the cost of covering it with paper at Rs. 12 per m2 and with paper at the rate of 13.50 per m2 is Rs. 1,248. Find the dimensions of the box. 

Sum

Solution

Given dimensions of a rectangular box are in the ratio 4: 2 : 3
Therefore, the total surface area of the box = 2`[ 4x xx 2x + 3x + 4 xx 3x ]`
 = 2 ( 8x2 + 6x2 + 12x2 ) m

Difference between cost of  covering the box with paper at Rs. 12 per m2 and with paper at Rs. 13.50 per m2 = Rs. 1,248 
⇒ 52x2[ 13 .5 - 12 ] = 1248
⇒ `52 xx x^2 xx 1 . 5` = 1248
⇒ 78 x x2 = 1248 
⇒ x2 = `( 1248)/( 78)`
⇒ x2 = 16 
⇒ x = 4             ...[ length, width and height cannot be negative ]

Thus, the domensions of the rectungular box are : 4 x 4 m,  2 x 4 m, 3 x 4 m
Thus, the dimensions are 16 m, 8 m aand 12 m.   

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Chapter 21: Solids [Surface Area and Volume of 3-D Solids] - Exercise 21 (C) [Page 274]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 21 Solids [Surface Area and Volume of 3-D Solids]
Exercise 21 (C) | Q 10 | Page 274
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