Question

The dimensions of universal gravitational constant are........................

a. [L¹M⁰T⁰]

b. [L²M¹T⁰]

c. [L^-1M¹T^-2]

d. [L³M^-1T^-2]

Answer 1

(d) [L³M^-1T^-2]

`G=(Fr^2)/(Mm)`

`therefore[G]=([L^1M^1T^-2][L^2])/([M^2])=[L^3M^-1T^-2]`