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Question
The distance between Mumbai and Pune is 192 km. Travelling by the Deccan Queen, it takes 48 minutes less than another train. Calculate the speed of the Deccan Queen if the speeds of the two
train differ by 20km/hr.
Solution
Let the speed of the Deccan Queen be x km/hr.
According to the question:
Speed of another train=`(x-20)`km/hr
`∴192/(x-20)-192/x=48/60`
⇒`4/(x-20)-4/x=1/60`
⇒`(4x-4(x-20))/((x-20)x)=1/60`
⇒`(4x-4x+80)/(x^2-20x)=1/60`
⇒`80/(x^2-20x)=1/60`
⇒`x^2-20x=4800`
⇒`x^2-20x-4800=0`
⇒`x^2-(80-60)x-4800=0`
⇒`x^2-80x+60x-4800=0`
⇒` x(x-80)+60(x-80)=0`
⇒`(x-80)(x+60)=0`
⇒`x=80 or x=-60`
The value of
x cannot be negative; therefore, the original speed of Deccan Queen 180 km/hr.
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