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Question
The equation of a line passing through the origin and perpendicular to the line 7x − 3y + 4 = 0 is
Options
7x – 3y + 4 = 0
3x – 7y + 4 = 0
3x + 7y = 0
7x – 3y = 0
Solution
3x + 7y = 0
Explanation;
Hint:
Slope of the line of 7x – 3y + 4 = 0
= `(-7)/(-3)`
= `7/3`
Slope of its ⊥r = `(-3)/7`
The line passes through (0,0)
Equation of a line is
y – y1 = m(x – x1)
y – 0 = `(-3)/7(x - 0)`
y = `(-3)/7x`
⇒ 7y = − 3x
3x + 7y = 0
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