Question

The equation of the perpendicular bisector of line segment joining points A(4,5) and B(-2,3) is ______.

Options

• 2x - y +7 = 0

• 3x + 2y - 7 = 0

• 3x - y - 7 = 0

• 3x + y - 7 = 0

Answer 1

The equation of the perpendicular bisector of line segment joining points A(4,5) and B(-2,3) is 3x + y - 7 = 0.

Explanation:-

Any point (x, y) of perpendicular bisector will be equidistant from A & B.

`therefore sqrt((x-4)^2+(y-5)^2)=sqrt((x+2)^2+(y-3)^2)`

Solving we get -12x - 4y + 28 = 0

or 3x + y - 7 = 0