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Question
The equivalent resistance of the parallel combination of two resistors of 60Ω and 40Ω is _______.
A) 24Ω
(B) 100Ω
(C) 50 Ω
(D) 240Ω
Solution
Let R be the total resistance in parallel combination
`1/R = 1/R_1 = 1/R_2`
`1/R = 1/60 + 1/40 = 100/(60xx40) = 1/24`
R = 24Ω
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